Steelers quarterback Ben Roethlisberger, Raiders linebacker Kamerion Wimbley and Colts kicker Adam Vinatieri have been named the AFC players of the week for the final week of the regular season.
Roethlisberger earns the offensive player of the week award after he completed 15 of 22 passes for 280 yards with two touchdowns and no interceptions (a 141.3 passer rating) in the Steelers’ 41-9 win at Cleveland. This is Roethlisberger’s first player of the week award of the season, and the sixth of his career.
Wimbley gets the defensive player of the week award after he had seven tackles, three sacks and two tackles for a loss in the Raiders’ 31-10 win at Kansas City. His constant pressure helped force the Chiefs into two interceptions and just 86 receiving yards. It’s the first player of the week honor for Wimbley, the former Browns first-round draft pick who was traded to the Raiders during the offseason
Vinatieri earned his 13th career Special Teams Player of the Week award after he made three field goals of 40-plus yards, including a 43-yarder as time expired, in the Colts’ 23-20 victory over the Titans. It was Vinatieri’s 23rd career game-winning kick in the last minute of the fourth quarter or overtime. The kick also gave Vinatieri 501 points with the Colts, making him the seventh kicker in NFL history to have more than 500 points with two different teams (he scored 1,156 with the Patriots). Vinatieri went 26-for-28 on field goals this season.