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Gronk makes $2.5 million with All-Pro honor

Buffalo Bills v New England Patriots

FOXBORO, MA - DECEMBER 24: Rob Gronkowski #87 of the New England Patriots reacts after catching a touchdown pass during the second quarter of a game against the Buffalo Bills at Gillette Stadium on December 24, 2017 in Foxboro, Massachusetts. (Photo by Tim Bradbury/Getty Images)

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Patriots tight end Rob Gronkowski had 5.5 million reasons to have a big year. He did, and he earned every penny of his incentive package.

Gronkowski is the Associated Press first-team All-Pro tight end. This triggers the full $5.5 million incentive package from his 2017 contract adjustment.

Gronk previously had unlocked $3 million based upon gaining more than 1,000 receiving yards. Achieving All-Pro designation gives him the full $5.5 million.

Gronkowski is under contract with the Patriots through 2019. Another adjustment to his deal could be coming in the offseason.