Skip navigation
Favorites
Sign up to follow your favorites on all your devices.
Sign up

Brady, Suggs, Janikowski named AFC players of the week

New England Patriots v Miami Dolphins

MIAMI GARDENS, FL - SEPTEMBER 12: Tom Brady #12 of the New England Patriots calls a play during a game against the Miami Dolphins at Sun Life Stadium on September 12, 2011 in Miami Gardens, Florida. (Photo by Mike Ehrmann/Getty Images)

Getty Images

A 500-yard game, a three-sack performance and a 63-yard field goal were enough to earn Patriots quarterback Tom Brady, Ravens linebacker Terrell Suggs and Raiders kicker Sebastian Janikowski the AFC Player of the Week honors.

Brady completed 32 of 48 passes for 517 yards (fifth most in NFL history) and four touchdowns as the Patriots beat the Dolphins. It’s the 18th time Brady has been named Player of the Week, which ties him with Dan Marino for the second-most since the award was instituted in 1984. (Peyton Manning has the most Player of the Week honors, with 21.)

Suggs had three sacks and two forced fumbles in the Ravens’ 35-7 win over the Steelers. Both times he forced Ben Roethlisberger to fumble, the Ravens recovered in Steelers territory. This was Suggs’ third Player of the Week award.

Janikowski booted an NFL record-tying 63-yard field goal just before halftime of a game the Raiders would win 23-20 at Denver. The kick made Janikowski the first player in NFL history to have more than one 60-yard field goal; he also made one from 61 yards in 2009. This was Janikowski’s fourth Player of the Week award, having previously won it in Week Seven of 2008.